Hibernate Query Language-Where clause

Hibernate Query Language-where clause

Use:

We get records depending upon the given condition using where clause.

Problem:

To get student name who have passed in tamil.

We assume that the pass mark is above 50.

Procedure:

Note:

Already we have created project named as HibernateProject. Also we have created Folder for storing jsp and Hibernate files.

Step 1:

            Create Hibernate Reverse Engineering wizard

Step 2:

            Create HibernateUtil.java

Step 3:

            Create POJO class and mapping files

Step 4:           

            Create jsp file named as WhereExam

Include following coding into WhereExam

< %@page contentType="text/html" pageEncoding="UTF-8"% >
< !DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"
http://www.w3.org/TR/html4/loose.dtd >
< %@page import="org.hibernate.SessionFactory" % >
< %@page import="org.hibernate.Session" % >
< %@page import="org.hibernate.cfg.Configuration" % >
< %@page import="org.hibernate.*" % >
< %@page import="java.util.*" % >
< %@page import="Hiber.Student" % >
< html >
< head >
< title > Hibernate where clause Example < /title >
< /head >
< body >

< %
try
{
SessionFactory sessionFactory=new Configuration().configure().buildSessionFactory();
Session s=sessionFactory.openSession();
String sql="select stuname from Student student where tamil>50";

Query query=s.createQuery(sql);
List list=query.list();
out.println("Students who have passed in Tamil/n");
for(int i=0;i="" <=""

Check the result

Open mysql

Given below query

mysql > select stuname from Student where tamil>50;